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# Bases for design of heat exchangers and plants for the preparation of sugar syrup and caramel mass

Fundamentals of thermal calculations

When determining the flow rate of the coolant (steam) and the size of the heating surface of the heat exchanger, the calculated equations of heat balance and heat transfer are usually compiled.

Total heat spent on heating, dissolving and evaporation of the product moisture, considering heat loss generally expressed by the formula (in Joules) (1-9)

where Q1, Q2, Q3 - The relevant articles of the consumption of useful heat spent on heating, dissolving and evaporation of the constituent parts of the product, j;

Qп - heat loss by the outer surface of the apparatus into the environment by radiation and convection, j.

When calculating the continuous flow of heat units in all respects shall be calculated in W (J / s) or J / h.

Heat consumption for heating each component of the processed product is determined by the formula (in J) (1-10)

where G is the number of the corresponding component of the heating, kg;

c — specific heat capacity of the component, J / (kg * K);

tk and tн- final and initial component temperatures, ° С.

The heat capacity of the majority of products depends on the temperature. For example:

specific heat of sugar c = 1000 + 7,25t J / (kg * K) (1.11)

specific heat capacity of molasses c = 1714 + 5,76t J / (kg * K). (1.12)

The heat capacity of sugar solutions, including sugar syrup and caramel mass, depends on temperature and concentration. It can be calculated by the formula of V. V. Yanovsky [in J / (kg • K)]

c = 4190 - (2514-7,540t) * a, (1.13)

where a is the concentration of sugar in the solution, kg / kg.

The specific heat capacity of water in practical calculations can be taken equal to 4190 J / (kg • K) [1 kcal / (kg • deg)].

Heat consumption for the dissolution of crystals (eg, sugar) is determined by the formula (in J)

Q2= Gqк, (1-14)

where G is the amount of product, kg;

qk is the latent heat of dissolution or crystallization of 1 kg of product equal to 4190 sugar j.

Heat consumption for the evaporation of moisture (in joules) is determined by the formula

Qз =D2r, (1-15)

where D2 - the amount of evaporated moisture, kg;

r — concealed heat of vaporization, J / kg; determined by the table of thermodynamic properties of steam depending on temperature or pressure (see Appendix).

The amount of moisture evaporated (in kg) when changing product concentration can be determined by solving equations solids balance

Gc.в=G1a1=G2a2                         (1-16)

and the material balance equation

Then (1-17) (1-18) where Gc.в - amount of dry substances in the product, kg;

G1 - the amount of product to be evaporated, kg;

G2 - quantity of the finished product, kg;

a1- the initial content (concentration) of dry substances in the product, kg / kg;

а2 - final solids content in the finished product, kg / kg.

If the moisture evaporates from the surface of the solution without any appreciable change in its concentration, the

D2 = 3600KF (р - φр1) τ, (I-19)

where К - coefficient of proportionality, depending on the air velocity and the physical properties of the evaporated product, kg / (m X NUMX-s * MPa);

F - evaporation surface area, м2;

τ is the duration of the evaporation process, s;

р - the vapor pressure of the vaporized product, MPa, at ambient temperature (determined according to the table of the application);

р'- elasticity of saturated vapors of the evaporated product, MPa, at ambient temperature (determined according to the table of the annex);

φ — relative air humidity (cf = 0,65-7-0,75).

The coefficient of proportionality К Water can be determined by the formula

K= 0,0745 (ʋр)0,8, (1-20)

where ʋ is the air velocity, m / s;

ρ is the air density, kg / m3.

Upon evaporation of water, depending on the air velocity proportionality factor K has the following meanings:

 V 0,5 1,0 1,5 2,0 К 0,036 0,083 0,114 0,145

Heat losses to the environment through the outer wall by radiation and convection, the device can determine the formula (in watts)

Qп=Faαk(tArt tв) (1-21)

where Fa - area of ​​the outer surface of the apparatus, m2;

αк- heat transfer coefficient, W / (m X NUMX * K);

tArt and tв- temperature of the wall and ambient air, ° С.

The heat transfer coefficient (total), provided that the unit is indoors and tCt does not exceed 150 ° С, approximately

calculated according to the formula [in W / (m2 • K)]

αк - 9,76 + 0,07 (tArt -tв). (I-22)

The amount of heating steam per cycle for a batch of devices in which the steam is condensed completely determined by the formula (in kg) (1-23)

where Qcommon - total heat consumption for one cycle, including losses to the environment from dy, j;

i1"и i1'—Consistently the enthalpy of heating steam and condensate, J / kg (see annex).

All steam consumption for the same devices will be (in kg / h) (1-24)

where τ is the cycle time, h

In tempering machines operating with an established thermal conditions, heating steam is consumed only for compensation of losses of heat into the environment. Its flow rate (kg / hr) is determined by the formula (1-25)

where Qп - heat loss to the environment, W;

i ”- heating steam enthalpy, J / kg;

i'— enthalpy of condensate, J / kg.

Steam consumption for continuous devices (in kg / s) is defined by the formula (1-23). But in this case, the total heat flow Qcommon calculated in watts.

Consumption of heat transfer fluids (eg water) is determined by the formula (in kg / s) (1-26)

where c is the specific heat capacity of the coolant, J / (kg-K);

tн and tк- the initial and final temperature of the coolant, ° C.

Area aids heat exchange surface is determined from the equation of heat transfer through the wall

Qfloor=FkcrΔtτ (1-27)

where the heat transfer surface area of ​​the device (in m2) (1-28)

The duration of the thermal process in the apparatus of periodic action (in s) will be (1-29)

where Qfloor - consumption of useful heat in the apparatus, j;

F —the area of ​​the heat exchange surface of the apparatus, m2;

kWed - average heat transfer coefficient, W / (m2*K);

∆t is the average temperature pressure between the coolant and the heat receiving medium, ° С.

When calculating devices of continuous action, heat consumption is calculated in watts, in the formula (1-28) the duration of the process is taken as τ = 1с.

The average temperature difference ∆t depends on the nature of the thermal process. If during heat exchange between two streams, the initial and final temperatures of one stream are denoted by t1"And t1', and the second — through t2'and t2“, The process can be represented graphically for the cases of direct flow and backflow (Fig. 23). Fig. 23. The graph of the temperature change of coolants: a - with forward flow; b - with countercurrent; in - - at condensation of the heating steam.

With forward flow and countercurrent, as well as at a constant temperature of one of the media, for example, during the condensation of heating steam (Fig. 23, c), the average temperature difference is defined as the average logarithm by the formula (1-30)

here Δtб and Δtм - respectively, more or less temperature pressure between the coolants at the beginning and end of the heat exchange surface.

If <1,8, then the average temperature head can be determined as the arithmetic mean (1-31)

If then instead of formula (1-30), you can use the formula (1-32)

The heat transfer coefficient of heating medium to be heated through the monolayer wall [W / (m2 • K)] is determined by the formula

(1-33) (1-33)

where α1 - heat transfer coefficient from the heat carrier to the wall, W / (m X NUMX-K);

α2 - heat transfer coefficient from the wall to the heated medium, W / (m X NUMX-K);

s — wall thickness, m;

ƛ - coefficient of thermal conductivity of the wall material, W / (m * K).

When boiling the product in a batch apparatus due to changes in product concentration changes and the heat transfer coefficient, so the approximate calculations batch of devices should be the average heat transfer coefficient.

Bases for siropovarochnoy station

The required capacity of dispensers for supplying components of the syrup: sugar, molasses, water can be determined by jointly solving the material balance equations specified by the recipe, n servings of sugar and molasses in the syrup and the moisture balance equation that takes into account the moisture of the syrup, sugar and syrup.

The material balance equation for 1 hours for the case to be

П=Gsah+Gstalemate+Gwater                                   (1-34)

where P is the syrup capacity, kg / s;

Gsah, Gstalemate, Gwater   - respectively, the flow rate of sugar, pat and water supplied to the solvent, kg / s.

The proportion of sugar solids in the syrup and molasses according to the recipe (1-35)

moisture balance equation for syrup having a certain humidity, would

Ωс=Gsahωsah +Gstalemateωstalemate +Gwaterωwater                    (1-36)

where ωс, ωsah, ωtime ωwater- the moisture content of syrup, sugar and molasses, respectively; in the calculations, they can be taken within the following limits: ωс = 16 ÷ 18%, or 0,16 — 0,18 kg / kg; ωsah = 0,14 ÷ 0,15%, or 0,0014 — 0,0015 kg / kg ωstalemate= 18 ÷ 22%, or 0,18 - 0,22 kg / kg.

Solving the last three equations and substituting in equation (1-36) instead of Gstalemate and Gwater their expressions from equations (1-34) and (1-35), we obtain the required flow rate of sugar and, consequently, the performance of the dispenser (in kg / s) (1-37)

According to the consumption of sugar, the consumption of molasses is determined from the equation of the proportions of sugar and molasses (1-35), and the consumption of water is determined from the material balance equation (1-34).

The total amount of heat required to heat the components of the syrup, dissolving sugar crystals and compensation solvent heat losses to the environment is determined by the formula (Watts) (1-38)

where Gj - the number of components of the syrup supplied to the solvent, kg / s;

Δgj- change in the enthalpy of the syrup components, J / kg;

Gsah - the amount of sugar supplied to the solvent, kg / s;

gk - latent heat of dissolution of 1 crystals kg of sugar, j / kg (gк = 4190)

QП - heat loss to the environment from radiation and convection (in W)

defined by the formulas (1-21) and (1-22).

It should be borne in mind that in the formula (1-38) (1-39)

where Gsah, Gstalemate, Gwater - consumption of sugar, molasses, water (determined by the above formulas), kg / s;

Δgsah, Δgstalemate, Δgwater - respectively, changes in the enthalpy of sugar, molasses and water at the initial and final temperatures, j / kg. Enthalpy of said products (J / kg) in the initial and final temperature is defined as gBeg = cнtн and ghorse - withкtк. To do this, the heat capacity of sugar and molasses is first calculated using the formulas (1-11) and (1-12) at the final (/ k) and initial (/ n) temperatures. In this case, the initial temperature of sugar will be the air temperature of the room from which it is supplied; the initial temperature of the supplied molasses within the limits of 55 — 60 ° С, water 70 — 80 ° С.

The final temperature of the syrup components will be the boiling point of the syrup, which is determined by the developed boiling temperature diagram of caramel syrups depending on the desired humidity of the caramel syrup ωс and pressure p (Fig. 24) (in this case, for an open apparatus-solvent, the pressure is atmospheric - 100 kPa). For example, at a humidity of 16% syrup and atmospheric pressure, its boiling point according to the indicated schedule will be approximately 120 ° С.

When determining the parameters of heating steam, it should be borne in mind that the steam temperature should be approximately 15 — 20 ° С above the boiling point of the syrup; Thus, in this case, the temperature of the heating steam will be: tп = 120 + 20 = 140 ° С.

The steam consumption for the solvent is determined by the formula (1-23), as for the apparatus of continuous action. When calculating the steam flow rate based on the adopted heating steam temperature, using the application table, first determine the required heating pressure p, and then use the same table to find the heating vapor enthalpy i ”1 and condensate I '1.

The surface area of ​​the heating solvent is defined as the heating surface of the continuous apparatus, and only the useful heat is taken into account (without loss to the environment).

For this case the useful heat for the solvent of the formula (1-38) is (in watts) (1-40)

Then the formula for determining the heating surface of the solvent will be (in m2). (1-41)

where kн- heat transfer coefficient when heated, W / (m X NUMX-K) (you can take an average of kн = 1500 ÷ 1740);

∆t is the average logarithmic temperature difference between the heat carrier (heating steam and the mixture - syrup, ° C; is determined by the formulas (1-30) and (1-31).

In our case (1-42)

where Δt1 = tп - tн.cm (Where tн.cm - initial average temperature of the mixture of syrup components);

Dt2 = tп- tк.cm (Where tk.sm - boiling point of syrup);

tп - temperature of heating steam, ° С.

It should be borne in mind that the average temperature of the mixture (in this case, the mixture of syrup components - sugar, water and syrup) loaded into the solvent, is determined from the equation of the heat balance of the mixture or is given in simplified calculations.

heat balance equation for the mixture in this case would br follows: or (1-43)

where the average temperature of the mixture (in ° C) (1-44)

where P is the amount of the mixture, kg / s;

Qsah, Qstalemate, Qwater - accordingly, the amount of heat introduced into the mixture by sugar syrup and water, W;

сcm- specific heat capacity of the mixture, J / (kg * K).

The remaining symbols are met before.

The required motor power for water solvent mixer blades determined by the formula (1-6).

The geometric volume V (in m3) Operating sugar atmospheric pressure of the solvent is determined by the formula (1-45)

where Gsah and Gwater - consumption of sugar and water, kg / h;

τр - the duration of dissolution, h (mp = 0,5-g-1,0); p is the density of the mixture of sugar and water, kg / m X NUMX;

ρ - fill factor (<p = 0,7 -g 0,8).

The length of the coil in the hinge connected buses-1 station is determined based on the duration of dissolution of sugar

L = ʋcτρ                                                            (1-46)

where ʋc - the average velocity of the mixture in the coil pipe, m / s (ʋc = 0,55 ÷ 0,65).

The diameter of the coil pipe d (in m) is found from the equation P hour stroke mixture through its cross-sectional area (1-47)

hence (1-48)

Bases for karamelevarochnoy station

To calculate the caramel station, it is first necessary to determine its performance taking into account possible caramel mass losses on all sections of the line. The approximate calculation sequence is as follows:

1.Opredelenie ready for hourly productivity caramel line with the time line for the cleaning equipment (kg / h): (1-49)

where Pcm - given shift line capacity, kg per shift;

τcm - shift work time (h) minus approximately 15 min (0,25 h) for cleaning the line equipment.

2. Determining the amount of caramel mass processed on the line per hour for a given percentage of filling in the finished caramel (in kg / h), (1-50)

where inн - the specified content of the filling in the finished caramel,%.

Accordingly, the capacity of the equipment for preparing the filling for this line, i.e. the amount of fruit and berry filling supplied to the line, will be (in kg / h) (1-51)

3. Determination of the hourly amount of caramel mass processed on the line in a dry matter, taking into account the desired moisture content of the caramel mass and the loss of dry substances (in kg / h) (1-52)

where ωк- given humidity of the finished caramel mass,%;

α is the caramel mass loss rate for dry matter on the line,% (taken approximately within 1,67 — 1,7%).

According to the formula (1-52) may be defined as the performance of individual sections or lines of machines and apparatus in view of the loss of product in the dry matter from the end portion of the line before or machines.

4. Determination of the hourly productivity of the caramel station by the caramel mass (in kg / h), taking into account the given humidity of the finished mass (1-53)

5. The determination from the dry matter balance equation (1-16) of the syrup consumption, i.e. the amount of syrup that must be supplied from the syrup station to the vacuum coil. Since the concentration of any solution (in kg / kg) is

a = (100-ω) / 100

where ω is the humidity of the solution,%,

the solids balance equation for this case is

Gc (100 - ωс) = Gк (100 - ωк), Where the required amount of caramel syrup will be

Gc = Gk (100- ωк) / (100 - ωс) (1-54)

here ωс - moisture content of caramel syrup,%.

Calculation of coil vacuum apparatus continuous conducted in the following order.

The equation of thermal balance for the coil vacuum unit with boiling caramel mass will (1-55)

where Gс, Gк - the amount of syrup supplied for boiling and the finished caramel mass produced, kg / s;

сс и ск - specific heat capacity of syrup and caramel mass, J / (kg-K)

tc, Tk - temperature of syrup and caramel mass, ° С;

i ”1i '1 —Entalpia of heating steam and condensate, J / kg;

D2 - the amount of evaporated moisture (secondary steam), kg / s;

i2 - enthalpy of secondary steam, J / kg;

D is the heating steam consumption, kg / s;

Qп - heat loss by the apparatus into the environment, watts.

The left side of the heat balance equation (1-55) expresses the heat parish:

Gс,c, Tc - heat introduced into the device by syrup, W;

Di1 - heat introduced into the apparatus by heating steam, W.

Members of the right-hand side of the equation indicate the article of this heat flow:

Gk,k, Tk - heat carried away with the finished caramel mass, W;

D2i2 - heat carried away with secondary steam, W;

Di1- heat carried away with condensate resulting from condensation of heating steam, W;

Qп - heat leaving in environment (losses), W.

Consumption of heating steam for the machine (in kg / s) is determined from the heat balance equation (1-55) (1-56)

caramel syrup temperature tсSupplied to the coil unit is determined on the schedule (see. Fig. 24) depending on the desired moisture syrup at atmospheric pressure (cm. Solvent races).

The boiling point of the cooked candy mass tк determined on the same schedule, depending on the desired final moisture caramel mass and vacuum in the vacuum chamber in the apparatus. In this residual pressure (kPa)

ρо = 100 - B,                             (I-57)

where B is the specified vacuum in the vacuum chamber of the apparatus, kPa.

The heat capacity of syrupс and caramel mass withк determined by the formula (1-13) heat capacity of sugar solutions.

The number of secondary steam (water evaporated) is determined from the material balance formula of the equation (1-18).

vapor Eytalpiya i2”Is determined depending on the residual (absolute) pressure in the vacuum chamber according to the application table.

Heating steam enthalpy i1”And condensate i1'is determined by the same table, depending on the adopted pressure of the temperature of the heating steam.

The temperature of the heating steam supplied to the vapor space of the heating part of the coil vacuum apparatus should be 15 — 20 ° С higher than the boiling temperature of the caramel mass found earlier (practically, the temperature of the heating steam should be

limits 158 — 159 ° С, which corresponds to an overheating heating pressure up to 0,6 MPa). This must be borne in mind when determining the parameters of the heating steam.

The loss of heat to the environment unit Qп determined by the formula (1-21) or take the experimental data.

Thus determined the value of all variables in the formula (1-56), calculate steam consumption.

The area of ​​the heat transfer surface coil vacuum apparatus (in m2) when boiling syrup is determined from the equation of heat transfer through the wall by the formula (1-28) (1-58)

Qfloor - consumption of useful heat (excluding losses), W;

k is the heat transfer coefficient of the coil; established by trial. For approximate calculations, it can be taken equal depending on the diameter of the coil 350 - 1000W / (m2 • K);

∆t — average temperature difference between the heating steam, syrup and caramel mass, ° С; is determined by the formulas (1-30) and (1-31).

Having determined the diameter of the coil pipe by the formula (1-48) at the screen speed in the pipe ʋ = 1,0 m / s, the geometrical dimensions of the coil are determined from the found value of the heat exchange surface.

The length of the coil, specifying pipe diameter according to GOST, is calculated as follows (in m) (1-59)

Where dн - outer diameter of the coil pipe. The length of the coil is usually taken within 800 — 1000 of the coil pipe diameters.

Nominal diameter of the coil DWed = 680 mm and a pitch of the coil can be found round the corner lifting coil In this case, 5 is taken to be 1,5 — 2,0 with? N- The length of a coil loop / (in m) will be (1-60)

The number of turns of the coil (1-61)

coil height (in m) will be (1-62)

where hconstr - a constructive additive taking into account the height of stamped bottoms.

Case diameter of the heating portion (VM) (1-63)

Finally, the diameter of the body of the heating part of the apparatus is taken to the nearest diameter of standard stamped bottoms. The geometric volume of the vacuum chamber of the apparatus is determined by the straight lines of its vapor space Rv [in m3/ (h • m3)] (1-64)

D2- amount of secondary steam, kg / h;

ʋ2 - specific volume of secondary steam, m3/ Kg;

V — volume of vacuum chamber, m3.

At atmospheric pressure, Rv = 8000 m3/ (M3 • h). Under vacuum, the vacuum chamber is Rv = 8000φ, where φ is a coefficient depending on the residual pressure values ​​in the vacuum chamber (when boiling caramel masses is approximately 0,85).

Then from (1-64) the volume of the vacuum chamber (in m3) will be (1-65)

The inner diameter of the vacuum chamber housing dв adopted for structural reasons, or depending on the diameter of standard stamped bottoms.

The height of the vacuum chamber body (in m) will (1-66)

The wall thickness (in m) of the housing of the heating portion of the apparatus as a thin-walled cylindrical vessel operating under internal overpressure, calculated by the formula (1-67)

where p is the pressure in the apparatus, MPa;

Dв - internal diameter of the case, m;

δz- permissible tensile stress, MPa;

φ is the strength coefficient of the weld (cf = 0,7 - g 0,8);

с - increase in corrosion, m.

Performance vacuum apparatus of the finished caramel mass (in kg / h) can be determined using the following form (1-68)

where gс= Cсtc - enthalpy of syrup entering boiling, J / kg;

gk.м = cкtк - Enthalpy of the finished caramel mass, j / kg;

tп - temperature of heating steam, ° С.

The condenser thermal mixing process takes place, which can be expressed by the following equation thermal balance (see. Diagram of ris.21) (1-69)

from the cooling water flow into the mixing condenser is (in kg / s) (1-70)

where D2 - the amount of condensed secondary steam, kg / s;

і2 - enthalpy of secondary steam, J / kg;

c is the specific heat capacity of water, J / (kg-K) (c = 4190);

t and t2K - the initial and final temperature of the cooling water, ° С (final water temperature t2K condensation is temperature).

The feed to the condenser cooling water W in an amount from an initial temperature t as drip down and condensing the steam is heated to a final temperature t2K, which in direct-flow condensers on 5 — 6 ° С is lower than the temperature of the condensed vapor.

The internal diameter of the capacitor (vm) is determined by the formula (1-71)

where ρп - steam density, kg / m 3;

ʋ - steam velocity in the condenser, m / s (ʋ = 20 ÷ 25).

The amount of air (in kg / s) pumped out of the condenser by a vacuum pump is determined by the formula (1-72)

Air flow rate (in m3/ c) from the condenser to the pump is determined by the formula (1-73)

where Gв - the amount of incoming air, kg / s;

288 is the gas constant for air, J / (kg-K);

tв - air temperature, ° С; for direct flow mixing capacitors TV = t2k . Ie leaving water temperature from the condenser.;

рв - partial air pressure, Pa.

Partial pressure of air (in Pa) can be defined by the formula

Рв = Pа- Rп                                             (I-74)

where pа - absolute (residual) pressure in the vacuum chamber and condenser, Pa;

рп - partial pressure of steam, Pa, which is taken to be equal to the pressure of saturated steam at air temperature.

In the vapor-air mixture in the condenser, the partial air pressure can also be determined from the equation (1-75)

here Vacuum Pump capacity to pump air-water mixture (in m3/ No) (1-76)

where the diameter of the pump piston (in m) (1-77)

where p is the density of the air-water mixture, kg / m X NUMX;

s - piston stroke, m;

W - cooling water consumption, kg / s;

D2- amount of condensate, kg / s;

Vв - the amount of exhaust air m3 / s;

n is the number of double strokes per minute;

ƛ0 - filling ratio (ƛ0 = 0,7 ÷ 0,8).

When determining the piston diameter by the stroke of the piston and the number of double strokes of the piston are set (according to the pump characteristic from the literature or reference data).

## One answer to “Basics of calculating heat exchangers and stations for the preparation of sugar syrups and caramel mass” Luciawrites:

Hello, where is the reference bibliograph for the equation VV Yanovsky?
Thanks!

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